Mathématiques

Question

bonsoir j ai besoin d aide poir demain.
Developpé puis reduire :
A=(x-5)²+(4x-1)(2x-10)
mercie beaucoup ​

2 Réponse

  • bjr

    A = (x - 5)²+(4x - 1)(2x - 10)  

      = x² - 10x + 25 + 8x² -40x - 2x + 10

    = x² + 8x² -10x -40x - 2x + 25 + 10  

    = 9x² - 52x + 35

  • A=(x-5)²+(4x-1)(2x-10)

    =(X×X)-(X×5)+(5×5)-(5×X)+(4X-1)(2X-10)

    =X^2-5X+25-5X+(4X-1)(2X-10)

    =X^2-10X+25+(4X-1)(2X-10)

    =X^2-10X+25+(4X×2X)-(4X×10)-(1×2X)+(1×10)

    =X^2-10X+25+8X^2-40X-2X+10

    =9X^2-10X+25-40X-2X+10

    =9X^2-50X+25-2X+10

    =9X^2-52X+25+10

    =9X^2-52X+35

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