if 32x^-4 = 8x^-6 find x​

Réponse :

Hello

32x^-4 = 8x^-6

32x^-4-8x^-6=0; x≠0

32×[1/x⁴]-8[1/x^6]=0

32/x⁴-8/x^6=0

(32x²-8)/x^6=0

32x²-8=0

32x²=8

x²=8/32=1/4

x==1/2

Ou x==-1/2

Les solutions finale sont

[tex]x_1=1/2 , x_2=-1/2[/tex]

Hi !

First of all, we need to get rid of those minus next to the power.

To do that, use this rule : [tex]x^{-a} = \frac{1}{x^a}[/tex]

You will get : [tex]\frac{32}{x^4} = \frac{8}{x^6}[/tex]

Now, we need to get rid of those fractions : use the rule of cross-multiplication.

You will get : [tex]32x^6 = 8x^4[/tex]

Now move [tex]8x^4[/tex] on the left and factorize.

You will get an equation with product which is equals to 0

Now you can solve it easily !

Hope it helped (sorry if I did some English mistakes i'm French)